Mẹo Hướng dẫn From the following which square number is divisible by 6 9 15 a 90 b 180 c 720 d 900 2022
Hoàng Thế Quang đang tìm kiếm từ khóa From the following which square number is divisible by 6 9 15 a 90 b 180 c 720 d 900 được Update vào lúc : 2022-11-18 07:24:02 . Với phương châm chia sẻ Bí quyết Hướng dẫn trong nội dung bài viết một cách Chi Tiết 2022. Nếu sau khi tham khảo nội dung bài viết vẫn ko hiểu thì hoàn toàn có thể lại Comments ở cuối bài để Tác giả lý giải và hướng dẫn lại nha.Solution:
Nội dung chính Show- For each of the following numbers, find the smallest
whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained. (i) 252 (ii) 180 (iii) 1008 (iv) 2028 (v) 1458 (vi) 768Which square number is divisible by each of the numbers 6 9 15?What is the least perfect square exactly divisible by each of the number 6 9 15 and 20?What is the smallest square number divided by 6 9 and 10?What is the smallest square number divisible by 2456 and 9?
We have to find the smallest whole number by which the number should be multiplied so as to get a perfect square number
To get a perfect square, each factor of the given number must be paired.
(i) 252
Hence, prime factor 7 does not have its pair. If 7 gets a pair, then the number becomes a perfect square. Therefore, 252 has to be multiplied by 7 to get a perfect square.
So, perfect square is 252 × 7 = 1764
1764 = 2 × 2 × 3 × 3 × 7 × 7
Thus, √1764 = 2 × 3 × 7 = 42
(ii) 180
Hence, prime factor 5 does not have its pair. If 5 gets a pair, then the number becomes a perfect square. Therefore, 180 has to be multiplied by 5 to get a perfect square.
So, perfect square is 180 × 5 = 900
900 = 2 × 2 × 3 × 3 × 5 × 5
Thus, √900 = 2 × 3 × 5 = 30
(iii) 1008
Hence, prime factor 7 does not have its pair. If 7 gets a pair, then the number becomes a perfect square. Therefore, 1008 has to be multiplied by 7 to get a perfect square.
So, perfect square is 1008 × 7 = 7056
7056 = 2 × 2 × 2 × 2 × 3 × 3 × 7 × 7
Thus, √7056 = 2 × 2 × 3 × 7 = 84
(iv) 2028
Hence, prime factor 3 does not have its pair. If 3 gets a pair, then the number becomes a perfect square. Therefore, 2028 has to be multiplied by 3 to get a perfect square.
So, perfect square is 2028 × 3 = 6084
6084 = 2 × 2 × 13 × 13 × 3 × 3
Thus, √6084 = 2 × 13 × 3 = 78
(v) 1458
Hence, prime factor 2 does not have its pair. If 2 gets a pair, then the number becomes a perfect square. Therefore, 1458 has to be multiplied by 2 to get a perfect square.
So, perfect square is 1458 × 2 = 2916
2916 = 3 × 3 × 3 × 3 × 3 × 3 × 2 × 2
Thus, √2916 = 3 × 3 × 3 × 2 = 54
(vi) 768
Hence, prime factor 3 does not have its pair. If 3 gets a pair, then the number becomes a perfect square. Therefore, 768 has to be multiplied by 3 to get a perfect square.
So, perfect square is 768 × 3 = 2304
2304 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
Thus, √2304 = 2 × 2 × 2 × 2 × 3 = 48
☛ Check: NCERT Solutions for Class 8 Maths Chapter 6
Video Solution:
For each of the following numbers, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained. (i) 252 (ii) 180 (iii) 1008 (iv) 2028 (v) 1458 (vi) 768
[embed]https://www.youtube.com/watch?v=hcwcxEsMG1o[/embed]
NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.3 Question 5
Summary:
For each of the following numbers, (i) 252 (ii) 180 (iii) 1008 (iv) 2028 (v) 1458 (vi) 768 the smallest whole number by which it should be multiplied so as to get a perfect square number and the square root of the square number so obtained are as follows: (i) 7; √1764 = 42 (ii) 5; √900 = 30 (iii) 7; √7056 = 84 (iv) 3; √6084 = 78 (v) 2; √2916 = 54 and (vi) 3; √2304 = 48
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